更新时间:2023-02-18 16:07:24
您应该做这样的事情。
public static String listToString(List<?> list) {
String result = "+";
for (int i = 0; i < list.size(); i++) {
result += " " + list.get(i);
}
return result;
}
和传递名单 listToString的参数()
。您的可以的技术上延长的ArrayList
(无论是与一个匿名类或具体的)和实施的toString
自己,但似乎没有必要在这里。
and pass the list in as an argument of listToString()
. You can technically extend ArrayList
(either with an anonymous class or a concrete one) and implement toString
yourself, but that seems unnecessary here.