是的，这是正确的方式。 >

请参阅这里：

http://www.javascriptkit.com/javatutors/error2.shtml

以及如何查看更多内容的解释

http： //www.javascriptkit.com/javatutors/error3.shtml

他们的例子：

  window.onerror = function（msg，url，linenumber）{
 alert（'错误消息：'+ msg +'\\\
URL：'+ url +'\\\
Line Number：'行号+）; 
返回true; 
} 
 

如果您希望在单个弹出窗口中显示错误列表，这很棘手。

由于错误是1乘1，您需要执行以下操作：

• 有 window.onerror 某些数组中的处理程序存储错误详细信息



• 定期检查数组 - 通过一个计时器，或者每个N点调用 window.onerror 处理程序，或两者。

  
  
  

  当检查发生，处理整个数组，根据需要显示内容，并清空数组

I want to display script errors in a popup alert instead of showing them in the browser console.

window.onerror = function() {
  var message = /* get error messages and put them here */;
  alert(message);
  return true;
};

Yes, that is the correct way.

See the reference here:

http://www.javascriptkit.com/javatutors/error2.shtml

And explanation of how to see more details of the error here:

http://www.javascriptkit.com/javatutors/error3.shtml

Their example:

window.onerror = function(msg, url, linenumber) {
    alert('Error message: '+msg+'\nURL: '+url+'\nLine Number: '+linenumber);
    return true;
}

If you wish to display a LIST of errors in a single pop-up, it's trickier.

Since the errors occue 1 by 1, you need to do the following:

• have window.onerror handler store error details in some array

• Check that array periodically - either via a timer, or on every N'th call of window.onerror handler, or both.

  When the check happens, process entire array, display contents as desired, and empty out an array