您需要首先实际运行查询:

you need to actually run the query first:

$sql= "INSERT INTO `database`.`table`(Columns) VALUES (Values)...";
$result = mysql_query($sql);

然后在那之后:

$id = mysql_insert_id();
echo $id

如果您仍有问题，请告诉我.

Let me know if you have still problems.