不要将字符串传递给Date构造函数，众所周知，它不擅长于解析字符串。 IE 8完全不会解析ISO 8601格式的字符串，并返回 NaN 。编写自己的解析器非常简单：

Do not pass strings to the Date constructor, it is notoriously bad at parsing strings. IE 8, for one, will not parse ISO 8601 format strings at all and return NaN. It's really simple to write your own parser:

function parseISOString(s) {
  var b = s.split(/\D+/);
  return new Date(Date.UTC(b[0], --b[1], b[2], b[3], b[4], b[5], b[6]));
}

请注意，如果时间是19：38：34.203 UTC和您的时区是UTC +0530，则该时区中的时间是第二天的01:08:34，因此日期有所不同。例如，对于一个在澳大利亚东海岸但没有遵守夏令时的人（即UTC +10），它相当于：

Note also that if the time is 19:38:34.203 UTC and your timezone is UTC +0530, then the time in that timezone is 01:08:34 am on the following day, hence the difference in dates. For example, for a person on the east coast of Australia but not observing daylight saving (i.e. UTC +10), it's equivalent to:

4 November, 2014 05:38:34

编辑

因此，如果要将其恢复为ISO日期，则可以使用 getISO * 方法来创建适合的格式，例如

Edit

So if you want to return it to an ISO date, you can use the getISO* methods to create whatever format that suits, e.g.

function isoFormatDMY(d) {  
  function pad(n) {return (n<10? '0' :  '') + n}
  return pad(d.getUTCDate()) + '/' + pad(d.getUTCMonth() + 1) + '/' + d.getUTCFullYear();
}

var s = '2014-11-03T19:38:34.203Z';
var date = parseISOString(s);

console.log(isoFormatDMY(date)) // 03/11/2014

或使用ES5的 toISOString ：

or use ES5's toISOString:

 parseISOString('2014-11-03T19:38:34.203Z').toISOString(); // 2014-11-03T19:38:34.203Z

适用于ES5之前版本浏览器的简单polyfill：

A simple polyfill for pre ES5 browsers:

if (!Date.prototype.toISOString) {

  Date.prototype.toISOString = function() {

    var d = this;

    // Padding functions 
    function pad(n) {return (n<10? '0' :  '') + n}
    function padd(n){return (n<100? '0' : '') + pad(n)}

    return d.getUTCFullYear() + '-' + pad(d.getUTCMonth() + 1) + '-' + pad(d.getUTCDate()) +
           'T' + pad(d.getUTCHours()) + ':' + pad(d.getUTCMinutes()) + ':' + 
           pad(d.getUTCSeconds()) + '.' + padd(d.getMilliseconds()) + 'Z';
  }
}