查找/主页/测试-regextype POSIX扩展-regex'^ *测试\\ .LOG \\。[0 -9] {4}  -  [0-9] {2}  -  [0-9] {2} \\拉链'-mtime +3
 

1. -name 使用的球状的前pressions，
   又名通配符。你需要的是
   -regex ​​


2. 要为你打算，您使用的时间间隔
   需要告诉找到使用的扩展
   通过经常防爆pressions 的
   -regextype POSIX扩展标志


3. 您需要跳脱出周期
   因为在正则表达式一个时期有
   的任何单一的特殊含义
   字符的。你需要的是一个
   文字期内表示\\。


4. 要只匹配那些文件
   的大于的比老3天，你需要preFIX以 + 为你的电话号码
   在 -mtime +3 。

概念验证

  $找到。 -regextype POSIX扩展-regex'^ *测试\\ .LOG \\ [0-9] {4}  -  [0-9] {2}  -  [0-9] {2} \\拉链。
./test.log.1234-12-12.zip
 

I was trying to find all files dated and all files 3 days or more ago.

find /home/test -name 'test.log.\d{4}-d{2}-d{2}.zip' -mtime 3

It is not listing anything. What is wrong with it?

find /home/test -regextype posix-extended -regex '^.*test\.log\.[0-9]{4}-[0-9]{2}-[0-9]{2}\.zip' -mtime +3

1. -name uses globular expressions, aka wildcards. What you want is -regex
2. To use intervals as you intend, you need to tell find to use Extended Regular Expressions via the -regextype posix-extended flag
3. You need to escape out the periods because in regex a period has the special meaning of any single character. What you want is a literal period denoted by \.
4. To match only those files that are greater than 3 days old, you need to prefix your number with a + as in -mtime +3.

Proof of Concept

$ find . -regextype posix-extended -regex '^.*test\.log\.[0-9]{4}-[0-9]{2}-[0-9]{2}\.zip'
./test.log.1234-12-12.zip