排序顺序似乎正确.我建议您检查一下编号:

The sorting order seems to be right. I would recommend you to review your numbering:

1 becomes 01

如果必须保留编号，也可以执行以下操作:

If you have to keep your numbering, you can also do:

key = lambda x: '.'.join(x.split('_')[1:3]).replace('job','').replace('q','')

a[np.argsort([float(key(i)) for i in a[:,0]])]

key()将执行以下操作:

key('BFT_job10_q0') --> 10.
key('BFT_job1_q0')  --> 1.
key('BFT_job13_q1') --> 13.1
key('BFT_job13_q0') --> 13.