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且构网 - 分享程序员编程开发的那些事

用两个时间字符串比较当前时间

更新时间:2023-02-22 12:56:49

首先,您必须将字符串"10:00","2:00"转换为当前日期的日期. 这可以例如完成使用以下方法(为简便起见,省略了错误检查):

First you have to convert the strings "10:00", "2:00" to a date from the current day. This can be done e.g. with the following method (error checking omitted for brevity):

- (NSDate *)todaysDateFromString:(NSString *)time
{
    // Split hour/minute into separate strings:
    NSArray *array = [time componentsSeparatedByString:@":"];

    // Get year/month/day from today:
    NSCalendar *cal = [NSCalendar currentCalendar];
NSDateComponents *comp = [cal components:NSYearCalendarUnit|NSMonthCalendarUnit|NSDayCalendarUnit fromDate:[NSDate date]];

    // Set hour/minute from the given input:
    [comp setHour:[array[0] integerValue]];
    [comp setMinute:[array[1] integerValue]];

    return [cal dateFromComponents:comp];
}

然后转换您的打开和关闭时间:

Then convert your open and closing time:

NSString *strOpenTime = @"10:00";
NSString *strCloseTime = @"2:00";

NSDate *openTime = [self todaysDateFromString:strOpenTime];
NSDate *closeTime = [self todaysDateFromString:strCloseTime];

现在,您必须考虑关闭时间可能在第二天:

Now you have to consider that the closing time might be on the next day:

if ([closeTime compare:openTime] != NSOrderedDescending) {
    // closeTime is less than or equal to openTime, so add one day:
    NSCalendar *cal = [NSCalendar currentCalendar];
    NSDateComponents *comp = [[NSDateComponents alloc] init];
    [comp setDay:1];
    closeTime = [cal dateByAddingComponents:comp toDate:closeTime options:0];
}

然后您可以按照@visualication在他的回答中所说的那样进行操作

And then you can proceed as @visualication said in his answer:

NSDate *now = [NSDate date];

if ([now compare:openTime] != NSOrderedAscending &&
    [now compare:closeTime] != NSOrderedDescending) {
    // now should be inside = Open
} else {
    // now is outside = Close
}