不是.现在，您可以将其放入一个函数中:

Nope. Now, you could put this into a function:

int readInt(std::istream& stream)
{
    int i;
    stream >> i; // Cross your fingers this doesn't fail
    return i;
}

// Then in your code:
obj.changeval(readInt(std::cin));

但是，当然，这仍然会创建一个int(只是将其移至readInt函数).

But of course, this still creates an int (it just moves it to the readInt function).

实际上，您已经创建了一些对象/内存空间供int居住，因此您可以读取并传递它.您可以在此处进行更改.但是，只需回答您的问题即可:

In reality, you have to create some object/memory space for the int to live in, so you can read it and pass it. Where you do this can be changed. But to simply answer your question: no.