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前置与前置C#中的发布增量

更新时间:2023-02-22 15:07:09

x--将为4,但在--x时刻将为3,因此最终将为2,那么您将拥有>

x-- will be 4, but will be 3 at the moment of --x, so it will end being 2, then you'll have

x = 4 - 2

顺便说一句,您的第一种情况是x = 4 + 6

btw, your first case will be x = 4 + 6

这是一个小示例,它将打印出每个零件的值,也许这样您会更好地理解它:

Here is a small example that will print out the values for each part, maybe this way you'll understand it better:

static void Main(string[] args)
{
    int x = 4;
    Console.WriteLine("x++: {0}", x++); //after this statement x = 5
    Console.WriteLine("++x: {0}", ++x); 

    int y = 4;
    Console.WriteLine("y--: {0}", y--); //after this statement y = 3
    Console.WriteLine("--y: {0}", --y);

    Console.ReadKey();
}

这将打印出来

x++: 4
++x: 6
y--: 4
--y: 2