您不能将 list 作为键，但可以使用 tuple 。另外，您不需要在列表上切片，而在子列表上。

You can't have list as key, but tuple is possible. Also you don't need to slice on your list, but on the sublist.

您需要前两个值 sublist [：2] 作为键，对应的值是索引2 sublist [2：]

You need the 2 first values sublist[:2] as key and the corresponding values is the sublist from index 2 sublist[2:]

new_dict = {}
for sublist in li:
    new_dict[tuple(sublist[:2])] = tuple(sublist[2:])

print(new_dict)  # {('a', 'b'): ('1', '2'), ('c', 'd'): ('3', '4')}

与dict理解相同

new_dict = {tuple(sublist[:2]): tuple(sublist[2:]) for sublist in li}
print(new_dict)  # {('a', 'b'): ('1', '2'), ('c', 'd'): ('3', '4')}