如果我理解正确，您只需要将句子拆分为单词，循环遍历每个单词，并检查它是否以所需字符结尾或以例如字符开头:

If I understand correctly, you just have to split up the sentence into words, loop over each one and check if it ends or starts with the required characters, e.g:

>>> sentence = ['AASFG', 'BBBSDC', 'FEKGG', 'SDFGF']
>>> [word for word in sentence.split() if word.endswith("GF")]
['SDFGF']

sentence.split()可能会替换为nltk.tokenize.word_tokenize(sentence)

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如何在单词的前面和后面得到单词

How can get word in-front of that and behind it

enumerate函数可用于为每个单词赋予一个数字，如下所示:

The enumerate function can be used to give each word a number, like this:

>>> print list(enumerate(sentence))
[(0, 'AASFG'), (1, 'BBBSDC'), (2, 'FEKGG'), (3, 'SDFGF')]

然后，如果您执行相同的循环，但保留索引:

Then if you do the same loop, but preserve the index:

>>> results = [(idx, word) for (idx, word) in enumerate(sentence) if word.endswith("GG")]
>>> print results
[(2, 'FEKGG')]

..您可以使用索引获取下一个或上一个项目:

..you can use the index to get the next or previous item:

>>> for r in results:
...     r_idx = r[0]
...     print "Prev", sentence[r_idx-1]
...     print "Next", sentence[r_idx+1]
...
Prev BBBSDC
Next SDFGF

您需要处理第一个或最后一个单词(if r_idx == 0，if r_idx == len(sentence))匹配的情况

You'd need to handle the case where the match the very first or last word (if r_idx == 0, if r_idx == len(sentence))