更新时间:2023-02-26 09:15:43
token =(\d +)
应该可以解决问题
也可以满足aplhas的需要要么执行以下操作:
To cater for aplhas as well you can do either:
token =([[a-zA-Z0-9 + / =] +)
即可匹配您期望的字符。这将匹配令牌=,然后捕获与字符类匹配的所有以下字符,即az,AZ,0-9,+,/和=。
token=([a-zA-Z0-9+/=]+)
to explicitly match on the characters you expect. This matches "token=" and then captures all following characters that match the character class, that is, a-z, A-Z, 0-9, +, / and =.
或
token =([[^&#] +)
以匹配除您知道的字符以外的任何字符可以完成令牌。这匹配 token =,然后捕获所有字符,直到第一个&
,#
或字符串的末尾
token=([^&#]+)
to match any character except for the ones you know can finish the token. This matches "token=" and then captures all characters until the first &
, #
or the end of the string.