您应该跟踪的两个 X 和是最大/最小元素的索引。无需后期处理，这簿记只是一个问题：

 如果（MAX＆LT;数字[X] [Y]）{
    最大=数字[X] [Y]
    MAXX = X;
    MAXY = Y;
}
 

I'm really stumped trying to find the index of the largest and smallest numbers of a 5x5 array with random numbers up to 1000 generated into them. Here my code:

import java.util.Random;

public class MaxMinArray {

    public static void main (String args[]) {

    int x=0, y=0, max=0, min=1000;;
    int[][] numbers = new int[5][5];

    for (x=0; x<numbers.length; x++) {                  //outer for          
        for(y=0; y<numbers.length; y++) {               //inner for    
            numbers[x][y]= (int)(Math.random()*1000);   //random generator

            if(max < numbers[x][y])                     //max number
                max = numbers[x][y];

            if(min>numbers[x][y])                       //min number
                min = numbers[x][y];

            int maxIndex = 0;

            for(int index = 1; index<numbers.length; index++)
                if(numbers[maxIndex]< numbers[index])
                    maxIndex = index;
            }
        }
        System.out.println("Max number in array:" + max + " ");
        System.out.println("Max number is in" + maxIndex + " ");
        System.out.println("Min number in array:" + min + " ");
    }
}

You should keep track of both the x and y index of the maximum/minimum element. No need to post-process, it's just a matter of bookkeeping:

if(max < numbers[x][y]) {
    max = numbers[x][y];
    maxX = x;
    maxY = y;
}