基本解决方案(可能不是***的解决方案，但至少是一个开始)

Basic solution (maybe not the best, but at least a start)

这个想法:从工作日开始到工作日结束，做一系列5分钟的练习.用0填充它.每次进行约会时，将其放置在5分钟内，并以1的形式放置在数组中.现在，您可以按块知道每个人是否有空.

The idea: make an array of 5-minute blocks from workday-start to workday end. Fill it with 0. Every time an appointment is made, put it in 5-minute blocks and put it in the array as 1. Now you know per block if someone is available.

//working hours
$start='10:45:00';
$end='18:45:00';
$start=strtotime($start);
$end=strtotime($end);

//end-start divided by 300 sec to create a 5 min block
$timesegments=($end-$start)/300;
//create the blocks-array
$blocks=array_fill_keys(range(0,$timesegments,5),0);

//an appointment
$app_start='10:45:00';
$app_end='11:00:00';

//make 5 minute blocks (note that workday start is 0!)
$app_start=(strtotime($app_start)-$start)/300;
$app_end=(strtotime($app_end)-$start)/300;

//put it in the blocks-array (+2 for 10 minute break)
for($i=$app_start;$i<$app_end+2;++$i){
    $blocks[$i]=1;
    }

echo '<pre>'.print_r($blocks,true).'</pre>';

这是非常基本的，没有任何检查，但我希望您可以使用它.

This is very basic and without any checks, but I hope you can use it.