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更新时间：2023-02-27 11:19:19
如果您用Google搜索 c#FFT ，您会发现可能的示例代码.这个看起来不错，我在此处找到了.有趣的是，您可以将每隔第二个位置带有0的数据用作表FFT的输入，如果需要的话，它可以期望复数.
If you do a google search for c# FFT you will find may code examples. This one looked quite good, which i found here. The interesting thing is, that you can use your data with the 0 on every second place as input for the Table FFT which expects complex numbers if you want.
始终确保您拥有的数据包具有2个样本计数的功效.
Always make sure you have data packages with power of 2 sample count.
/// <summary>
/// Compute the forward or inverse Fourier Transform of data, with data
/// containing complex valued data as alternating real and imaginary
/// parts. The length must be a power of 2. This method caches values
/// and should be slightly faster on than the FFT method for repeated uses.
/// It is also slightly more accurate. Data is transformed in place.
/// </summary>
/// <param name="data">The complex data stored as alternating real
/// and imaginary parts</param>
/// <param name="forward">true for a forward transform, false for
/// inverse transform</param>
public void TableFFT(double[] data, bool forward)
{
var n = data.Length;
// checks n is a power of 2 in 2's complement format
if ((n & (n - 1)) != 0)
throw new ArgumentException(
"data length " + n + " in FFT is not a power of 2"
);
n /= 2; // n is the number of samples
Reverse(data, n); // bit index data reversal
// make table if needed
if ((cosTable == null) || (cosTable.Length != n))
Initialize(n);
// do transform: so single point transforms, then doubles, etc.
double sign = forward ? B : -B;
var mmax = 1;
var tptr = 0;
while (n > mmax)
{
var istep = 2 * mmax;
for (var m = 0; m < istep; m += 2)
{
var wr = cosTable[tptr];
var wi = sign * sinTable[tptr++];
for (var k = m; k < 2 * n; k += 2 * istep)
{
var j = k + istep;
var tempr = wr * data[j] - wi * data[j + 1];
var tempi = wi * data[j] + wr * data[j + 1];
data[j] = data[k] - tempr;
data[j + 1] = data[k + 1] - tempi;
data[k] = data[k] + tempr;
data[k + 1] = data[k + 1] + tempi;
}
}
mmax = istep;
}
// perform data scaling as needed
Scale(data, n, forward);
}
/// <summary>
/// Compute the forward or inverse Fourier Transform of data, with
/// data containing real valued data only. The output is complex
/// valued after the first two entries, stored in alternating real
/// and imaginary parts. The first two returned entries are the real
/// parts of the first and last value from the conjugate symmetric
/// output, which are necessarily real. The length must be a power
/// of 2.
/// </summary>
/// <param name="data">The complex data stored as alternating real
/// and imaginary parts</param>
/// <param name="forward">true for a forward transform, false for
/// inverse transform</param>
public void RealFFT(double[] data, bool forward)
{
var n = data.Length; // # of real inputs, 1/2 the complex length
// checks n is a power of 2 in 2's complement format
if ((n & (n - 1)) != 0)
throw new ArgumentException(
"data length " + n + " in FFT is not a power of 2"
);
var sign = -1.0; // assume inverse FFT, this controls how algebra below works
if (forward)
{ // do packed FFT. This can be changed to FFT to save memory
TableFFT(data, true);
sign = 1.0;
// scaling - divide by scaling for N/2, then mult by scaling for N
if (A != 1)
{
var scale = Math.Pow(2.0, (A - 1) / 2.0);
for (var i = 0; i < data.Length; ++i)
data[i] *= scale;
}
}
var theta = B * sign * 2 * Math.PI / n;
var wpr = Math.Cos(theta);
var wpi = Math.Sin(theta);
var wjr = wpr;
var wji = wpi;
for (var j = 1; j <= n/4; ++j)
{
var k = n / 2 - j;
var tkr = data[2 * k]; // real and imaginary parts of t_k = t_(n/2 - j)
var tki = data[2 * k + 1];
var tjr = data[2 * j]; // real and imaginary parts of t_j
var tji = data[2 * j + 1];
var a = (tjr - tkr) * wji;
var b = (tji + tki) * wjr;
var c = (tjr - tkr) * wjr;
var d = (tji + tki) * wji;
var e = (tjr + tkr);
var f = (tji - tki);
// compute entry y[j]
data[2 * j] = 0.5 * (e + sign * (a + b));
data[2 * j + 1] = 0.5 * (f + sign * (d - c));
// compute entry y[k]
data[2 * k] = 0.5 * (e - sign * (b + a));
data[2 * k + 1] = 0.5 * (sign * (d - c) - f);
var temp = wjr;
// todo - allow more accurate version here? make option?
wjr = wjr * wpr - wji * wpi;
wji = temp * wpi + wji * wpr;
}
if (forward)
{
// compute final y0 and y_{N/2}, store in data[0], data[1]
var temp = data[0];
data[0] += data[1];
data[1] = temp - data[1];
}
else
{
var temp = data[0]; // unpack the y0 and y_{N/2}, then invert FFT
data[0] = 0.5 * (temp + data[1]);
data[1] = 0.5 * (temp - data[1]);
// do packed inverse (table based) FFT. This can be changed to regular inverse FFT to save memory
TableFFT(data, false);
// scaling - divide by scaling for N, then mult by scaling for N/2
//if (A != -1) // todo - off by factor of 2? this works, but something seems weird
{
var scale = Math.Pow(2.0, -(A + 1) / 2.0)*2;
for (var i = 0; i < data.Length; ++i)
data[i] *= scale;
}
}
}
/// <summary>
/// Determine how scaling works on the forward and inverse transforms.
/// For size N=2^n transforms, the forward transform gets divided by
/// N^((1-a)/2) and the inverse gets divided by N^((1+a)/2). Common
/// values for (A,B) are
/// ( 0, 1) - default
/// (-1, 1) - data processing
/// ( 1,-1) - signal processing
/// Usual values for A are 1, 0, or -1
/// </summary>
public int A { get; set; }
/// <summary>
/// Determine how phase works on the forward and inverse transforms.
/// For size N=2^n transforms, the forward transform uses an
/// exp(B*2*pi/N) term and the inverse uses an exp(-B*2*pi/N) term.
/// Common values for (A,B) are
/// ( 0, 1) - default
/// (-1, 1) - data processing
/// ( 1,-1) - signal processing
/// Abs(B) should be relatively prime to N.
/// Setting B=-1 effectively corresponds to conjugating both input and
/// output data.
/// Usual values for B are 1 or -1.
/// </summary>
public int B { get; set; }
/// <summary>
/// Scale data using n samples for forward and inverse transforms as needed
/// </summary>
/// <param name="data"></param>
/// <param name="n"></param>
/// <param name="forward"></param>
void Scale(double[] data, int n, bool forward)
{
// forward scaling if needed
if ((forward) && (A != 1))
{
var scale = Math.Pow(n, (A - 1) / 2.0);
for (var i = 0; i < data.Length; ++i)
data[i] *= scale;
}
// inverse scaling if needed
if ((!forward) && (A != -1))
{
var scale = Math.Pow(n, -(A + 1) / 2.0);
for (var i = 0; i < data.Length; ++i)
data[i] *= scale;
}
}