您可以使用

You could use the next() function with a generator expression:

fruit_chosen = next((fruit['fruit'] for fruit in lst if fruit['color'] == 'yellow'), None)

这会将 first 水果字典分配为与fruit_chosen匹配，如果没有匹配，则为None.

This will assign the first fruit dictionary to match to fruit_chosen, or None if there is no match.

或者，如果省略默认值，则如果找不到匹配项，则next()将提高StopIteration:

Alternatively, if you leave out the default value, next() will raise StopIteration if no match is found:

try:
    fruit_chosen = next(fruit['fruit'] for fruit in lst if fruit['color'] == 'yellow')
except StopIteration:
    # No matching fruit!

演示:

>>> lst = [{'fruit': 'apple', 'qty':'4', 'color': 'green'},{'fruit': 'orange', 'qty':'6', 'color': 'orange'},{'fruit': 'melon', 'qty':'2', 'color': 'yellow'}]
>>> next((fruit['fruit'] for fruit in lst if fruit['color'] == 'yellow'), None)
'melon'
>>> next((fruit['fruit'] for fruit in lst if fruit['color'] == 'maroon'), None) is None
True
>>> next(fruit['fruit'] for fruit in lst if fruit['color'] == 'maroon')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
StopIteration