2月27日下午7:05，ying ... @ gmail.com < ying ... @ gmail.comwrote：

我有以下功能，但''dx = abs（i2 - i1）/ min（i2 ，

i1）''总是返回0，你能告诉我怎样才能将它从

整数转换成浮点数？


def compareValue（n1，n2）：

i1 = int（n1）

i2 = int（n2）


dx = abs（i2 - i1）/ min（i2，i1）

print dx

return dx< 0.05

x = x + 0.0

yi ***** @ gmail.com 写道：

我有以下功能，但是''dx = abs（i2 - i1）/ min（i2，

i1）''总是返回0，你能告诉我怎样才能将它转换成

要浮动的整数？

当一个分区中涉及两个整数时，结果也将是一个

分区。如果其中一个操作数是浮点数，那么结果将是一个

浮点数。因此，尝试将其中一个值投射到浮点数之前执行除法：
执行除法：


dx = float（abs（i2 - i1））/ min（i2 ，i1）


-Farshid

Farshid Lashkari写道：

当一个分区涉及两个整数时，结果也将是一个

分区。

我的坏，我的意思是结果也是*整数*


-Farshid

Hi, I have the following functions, but '' dx = abs(i2 - i1)/min(i2,
i1)'' always return 0, can you please tell me how can i convert it from
an integer to float?
def compareValue(n1, n2):
i1 = int(n1)
i2 = int(n2)

dx = abs(i2 - i1)/min(i2, i1)
print dx
return dx < 0.05

On Feb 27, 7:05 pm, "ying...@gmail.com" <ying...@gmail.comwrote:

Hi, I have the following functions, but '' dx = abs(i2 - i1)/min(i2,
i1)'' always return 0, can you please tell me how can i convert it from
an integer to float?

def compareValue(n1, n2):
i1 = int(n1)
i2 = int(n2)

dx = abs(i2 - i1)/min(i2, i1)
print dx
return dx < 0.05

x = x + 0.0

yi*****@gmail.com wrote:

Hi, I have the following functions, but '' dx = abs(i2 - i1)/min(i2,
i1)'' always return 0, can you please tell me how can i convert it from
an integer to float?

When two integers are involved in a division, the result will also be a
division. If one of the operands is a float, then the result will be a
float instead. So try casting one of the values to a float before
performing the division:

dx = float(abs(i2 - i1))/min(i2, i1)

-Farshid

Farshid Lashkari wrote:

When two integers are involved in a division, the result will also be a
division.

My bad, I meant the result will also be an *integer*

-Farshid