试试下面代码，没用函式库，直接作两次递回，第一次去空字串，第二次是去空对象，没细测过大量资料时的效能，但可得出你要的结果。再深层一些可再试试:

function isEmpty(obj) {
   return (Object.keys(obj).length === 0 && obj.constructor === Object);
}

function deleteEmptyString(test, recurse) {
    
    for (var i in test) {
        if (test[i] === '' ) {
            delete test[i];
        } else if (recurse && typeof test[i] === 'object') {
            deleteEmptyString(test[i], recurse);
        }
    }
       
}

function deleteEmptyObject(test, recurse) {
    
    for (var i in test) {
        if (isEmpty(test[i]) ) {
            delete test[i];
        } else if (recurse && typeof test[i] === 'object') {
            deleteEmptyObject(test[i], recurse);
        }
    }
       
}



var o = {
  a:1,
  b:{b_a:''},
  c:{c_a:1,c_b:''},
  //d:{d_a:1,d_b:'', d_c: { x:'', y:1}, d_d:{ z:'' } }
}



deleteEmptyString(o, true);
console.log(o);

deleteEmptyObject(o,true);
console.log(o);

参考自: http://***.com/ques...

http://***.com/ques...