要声明任何类型的向量，您需要将类型作为模板参数传递。在你的情况下，类型是 MachineList ：

To declare a vector of any type, you need to pass the type as a template parameter. In your case, the type is MachineList:

vector<MachineList> SS;

要添加一个实例，可以使用 push_back code>：

To add an instance, you can use for example push_back():

SS.push_back(MACHINELIST); // add the MACHIHELIST instance
SS.push_back(MachineList()); // add a default constructed MachineList.

在您的代码中， MACHINELIST MachineList

指针，你需要一个指针的向量：

Edit in response to comments: if you wanted to store pointers, you would need a vector of pointers:

vector<MachineList*> SS;

然后您可以添加条目：

MachineList* m = new MachineList;
SS.push_back(m);

您有责任删除指针，在适当的时候释放动态分配的资源。我建议使用智能指针，而不是原始指针，但你的代码中有更基本的问题。

You are responsible for deleting the pointer to deallocate the dynamically allocated resources at the appropriate moment. i would suggest using smart pointers instead of raw ones, but you have more fundamental problems in your code.