更新时间:2023-09-09 22:24:52
我想指出对其他论坛提供的答案感兴趣的人
I'd like to point those who are interested to this answer provided on another forum
S=sparse(1:N,idxM,1);
sumM=S.'*(M*S);
S=sparse(1:N,idxM,1);
sumM=S.'*(M*S);
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Credits (and useful discussion):