HI All。


我想编写一个代码来替换string.without使用字符串函数的单词


示例str ="这是字符串"删除是来自字符串并替换为was。

所以，最后str ="这是字符串。


Void replace（char * str，char * pattern1，char * pattern2）。


提前致谢。


Kin Parmar。

HI All.

I want to write a code which replace words from string.without use of string function

Example str = "This is string" remove "is" from string and replace with "was".
so, finally str = "This was string".

Void replace ( char * str , char * pattern1, char * pattern2).

Thanks in advance.

Kin Parmar.

好​​的，到目前为止你做了什么？


请询问有关sepcifice的问题，如果你有问题，请阅读发布指南还没有。


Savage

Ok,what have u done so far?

Please ask about a sepcifice quesution and please read posting guidelines if u haven''t already.

Savage

好​​的，到目前为止你做了什么？


请询问有关sepcifice质疑的问题，如果你还没有，请阅读发布指南。


Savage

Ok,what have u done so far?

Please ask about a sepcifice quesution and please read posting guidelines if u haven''t already.

Savage

我想从字符串中找出单词并用新单词替换。


就像明智一样，我有字符串"伟大的人在这里从那个替换人并把男人。


我在这里写简单的代码： -

但需要帮助： -

I want to find out word from string and replace with new word.

like wise, I have string " Great People here" from that replace "People" and put "Man".

I write simple code here :-
but need help :-

我想从字符串中找出单词并用新单词替换。


就像明智一样，我有字符串伟大的人在这里从那个替换人并把男人。


我在这里写简单的代码： -

但需要帮助： -


char * str ="这是字符串&quot ;;

char * pattern1 ="是&quot ;;

char * pattern2 =" was&quot ;;


int slen = strlen（str）;


for（int i = 0; i< slen; i ++）

{

for（int j = 0; j< slen; j ++）

{

if（pattern1 [i] == str [ j]）

{

// str [j] = pattern2 [i]; ///在这里需要帮助，如何替换字符串。


}

}


}

I want to find out word from string and replace with new word.

like wise, I have string " Great People here" from that replace "People" and put "Man".

I write simple code here :-
but need help :-

char* str = "this is string";
char* pattern1 = "is";
char* pattern2 = "was";

int slen = strlen(str);

for (int i = 0; i <slen; i++)
{
for (int j =0; j < slen; j++)
{
if (pattern1[i] == str[j] )
{
//str[j]=pattern2[i]; /// Want help here, how to replace string.

}
}

}

为了做你想做的事，你必须先将你的字符串标记，然后用空格作为代币。

例如


string ="这是一个字符串

标记化后的


string1->"这个

string2->"""

string3->" a"

string4->" string"

我想你不想用字符串函数来标记化吗？
>
Savage

In order to do what u want to do,u must first tokenize ur string,uisng a whitespace as a token.
e.g

string="This is a string"

after tokenizingL

string1->"This"
string2->"is"
string3->"a"
string4->"string"

I suppose u don''t want to use string function to tokenize?

Savage