更新时间:2023-09-13 10:37:04
提升到乘法和乘法都很好.在这一点上,我们被简化为 36-21+15.在这里我们必须记住,我们正在添加 -21.所以我们需要回到 -7 .当我建立我的数字列表(它处理一位以上的数字)时,我会在它前面的数字上加上减号.
All is well with raising to a power and multiplication. At that point we are simplified to 36-21+15. Here we must remember that we are adding -21. So we need to go back to -7 . When I build my list of numbers (it handles numbers of more than one digit) I add the minus sign to the number it precedes.
此代码不处理十进制数或括号.如果您愿意,我认为您可以添加除法运算符.
This code does not handle decimal numbers or parenthesis. I think you will be able to add the division operator, if you wish.
Private NumList As New List(Of Double)
Private OperatorList As New List(Of String)
Private Sub OpCode()
Dim Input = "14*3^2-7*3+15*3"
PopulateLists(Input)
Dim OpIndex As Integer
Dim NewNum As Double
Dim operators = {"^", "*", "+"} 'Note: no minus sign, the minus goes with the number
For Each op In operators
Do
OpIndex = OperatorList.IndexOf(op)
If OpIndex = -1 Then
Exit Do
End If
Select Case op
Case "^"
NewNum = NumList(OpIndex) ^ NumList(OpIndex + 1)
Case "*"
NewNum = NumList(OpIndex) * NumList(OpIndex + 1)
Case "+"
NewNum = NumList(OpIndex) + NumList(OpIndex + 1)
End Select
NumList.RemoveAt(OpIndex + 1)
NumList(OpIndex) = NewNum
OperatorList.RemoveAt(OpIndex)
Loop
Next
MessageBox.Show(NumList(0).ToString) 'Displays 150
End Sub
Private Sub PopulateLists(Input As String)
Dim strNum As String = ""
For Each c As Char In Input 'Be careful here, the IDE wants to add () at the end of this line - it doesn't belong
If Char.IsDigit(c) Then
strNum &= c
ElseIf c = "-" Then
OperatorList.Add("+") 'We are adding a negative number
NumList.Add(CDbl(strNum)) 'Add the last number we accumulated so we can start a new one with the minus sign
strNum = "-" 'Start a new number with the minus sign
Else 'The other operators are added to the list
OperatorList.Add(c)
NumList.Add(CDbl(strNum))
strNum = ""
End If
Next
NumList.Add(CInt(strNum)) 'The last number which will not be followed by an operator
End Sub