更新时间:2023-09-23 14:35:58
melt
, GroupBy
, resample
&填充
首先我们melt
(unpivot) 你的两个日期列合二为一.然后我们resample
按天计算:
melt
, GroupBy
, resample
& ffill
First we melt
(unpivot) your two date columns to one. Then we resample
on day basis:
melt = df.melt(id_vars=['id', 'age', 'state'], value_name='date').drop('variable', axis=1)
melt['date'] = pd.to_datetime(melt['date'])
melt = melt.groupby('id').apply(lambda x: x.set_index('date').resample('d').first())
.ffill()
.reset_index(level=1)
.reset_index(drop=True)
输出
date id age state
0 2019-02-17 123.0 18.0 CA
1 2019-02-18 123.0 18.0 CA
2 2019-02-19 123.0 18.0 CA
3 2019-02-20 123.0 18.0 CA
4 2019-02-21 123.0 18.0 CA
.. ... ... ... ...
119 2019-02-28 223.0 24.0 AZ
120 2019-03-01 223.0 24.0 AZ
121 2019-03-02 223.0 24.0 AZ
122 2019-03-03 223.0 24.0 AZ
123 2019-03-04 223.0 24.0 AZ
[124 rows x 4 columns]
编辑:
我不得不在一个项目中重新审视这个问题,看起来像使用 DataFrame.apply
和 pd.date_range
和 DataFrame.explode
是快了近 3 倍:
I had to revisit this problem in a project, and looks like using DataFrame.apply
with pd.date_range
and DataFrame.explode
is almost 3x faster:
df["date"] = df.apply(
lambda x: pd.date_range(x["start_date"], x["end_date"]), axis=1
)
df = (
df.explode("date", ignore_index=True)
.drop(columns=["start_date", "end_date"])
)
输出
id age state date
0 123 18 CA 2019-02-17
1 123 18 CA 2019-02-18
2 123 18 CA 2019-02-19
3 123 18 CA 2019-02-20
4 123 18 CA 2019-02-21
.. ... ... ... ...
119 223 24 AZ 2019-02-28
120 223 24 AZ 2019-03-01
121 223 24 AZ 2019-03-02
122 223 24 AZ 2019-03-03
123 223 24 AZ 2019-03-04
[124 rows x 4 columns]