为什么不只是为函数使用其他名称？如果没有实现，对于 CRTP 类的每个派生，您都会遇到编译错误。考虑以下内容：

Why not just use a different name for the function? Then you will have a compilation error for each derivation of CRTP class without and implementation. Consider this:

class Base
{
public:
    class Params
    {
    public:
        virtual ~Params() {}
    };

    virtual void myFunc( Params& p ) = 0;
};

template< typename T >
class CRTP : public Base
{
public:
    virtual void myFunc( Base::Params& p ) final override
    {
        typename T::Params& typedParams = dynamic_cast<typename T::Params&>( p );
        static_cast<const T*>( this )->myFuncImp( typedParams );
    }

};

class Imp : public CRTP<Imp>
{
public:
    class Params : public CRTP<Imp>::Params
    {
    public:
        virtual ~Params() {}

        int x, y, z;
    };
};

int main(int argc, char** argv)
{
    Imp imp;
}

由于没有 myFuncImp $，编译失败c $ c>由 Imp 提供。