更新时间:2023-10-04 16:42:10
p>在这种情况下,我不认为命名参数有效。所以你必须这样做:
I don't think that named parameters work in this case. So you'd have to do something like:
xlwb = xlApp.Workbooks.Open(filename,False,True,None,password)
xlwb = xlApp.Workbooks.Open(filename, False, True, None, password)
请参阅 http://msdn.microsoft。 com / en-us / library / office / ff194819.aspx 有关Workbooks.Open方法的详细信息。
See http://msdn.microsoft.com/en-us/library/office/ff194819.aspx for details on the Workbooks.Open method.