更新时间:2023-10-04 19:35:28
为了制作正确的JSON,请尝试:
`
$ result =从room_db中选择标题where hotel ='1'by id asc;
$ messages = array();
while($ message_data = mysql_fetch_assoc($ result)){
$ message = array(
'id'=> $ message_data ['userid'],
'title' => $ message_data ['title']
);
$ messages [] = $ message;
}
echo json_encode($ messages);
$ / code $ / pre
< p>在关闭方这样做: `
data1 = $。parseJSON(data);
if(data1.length === 0){
$('#table> #table_body')。append('< tr>< td colspan =4align =centerstyle =color:red> NO matching data< / td>< / tr>');
}
else {
for(var i = 0; i< data1.length; i ++)
{
$('#table> #table_body') .append('< tr id ='+ data1 [i] ['id'] +'>< td id ='+ data1 [i] ['id'] +'align =center < td>'+ data1 [i] ['title'] +'< / td>< / tr>');
$('#table')。append('< / tbody>');
`
According to my previous solved issue : Re-arrange mysql result in an expected format for hansontable. I'm going to re-format mysql result from
["Superior"],["Deluxe - City View"],["Deluxe - Balcony"],["Junior
Suite"],["Andaman Studio"]
into
["Superior","Deluxe - City View","Deluxe - Balcony","Junior Suite","Andaman Studio"]
From these codes:
$sql_rName="select title from room_db where hotel='1' order by id asc";
$result_rName=mysql_db_query($dbname,$sql_rName);
while($rec_rName=mysql_fetch_array($result_rName)){
$_rName=$rec_rName['title'];
$_array[]=$_rName;
}
echo "{\"data\": ".json_encode($_array)."}";
mysql Table : room_db
Please suggest.
ps. Thanks to Olaf Dietsche for all of these help.
To make a correct JSON, Try :
`
$result="select title from room_db where hotel='1' order by id asc";
$messages = array();
while($message_data = mysql_fetch_assoc($result)) {
$message = array(
'id' => $message_data['userid'],
'title' => $message_data['title']
);
$messages[] = $message;
}
echo json_encode($messages);
}
`
and on the reseiver side do this :
`
data1=$.parseJSON(data);
if(data1.length===0){
$('#table > #table_body').append('<tr><td colspan="4" align="center" style="color:red">NO matching data </td></tr>');
}
else{
for(var i=0;i<data1.length;i++)
{
$('#table > #table_body').append('<tr id="' + data1[i]['id'] +'"> <td id="' + data1[i]['id'] +'" align="center" <td>'+data1[i]['title']+'</td> </tr>');
}
}
$('#table').append('</tbody>');
`