如果我没错，你想根据 LoginTime 获得10个不同的用户。因此，您必须按 UserId 对数据进行分组，并获得 LoginTime 的最大值。

If i'm not wrong you want to get 10 distinct users based on LoginTime. So, you have to group data by UserId and get the max of LoginTime.

DateTime today12AM = new DateTime(2015,10,27,0,0,0);
DateTime today12PM = today12AM.AddDays(1); 
var logLst=EJE.LoginDetails
    .Where(m=>m.LoginTime>=today12AM && m.LoginTime<today12pm)>
    .GroupBy(m=> m.UserId)
    .Select(g=>new 
        {
            UserId = g.Key(),
            LoginTime = g.Max(t=>t.LoginTime)
        })
    .OrderByDescending(a=>a.LoginTime)
    .Take(10)
    .ToList();

试试！

Try!

var logLst = EJE.LoginDetails.Where(m=>m.UserID==userid).OrderByDescending(m=>m.LoginTime).Distinct().Take(10);

Enumerable.Distinct&LT; tsource&GT;方法（IEnumerable< tsource>） [ ^ ]



-KR

Enumerable.Distinct<tsource> Method (IEnumerable<tsource>)[^]

-KR