有关文本菜单：

的问题是，发件人参数指向的项目的被点击，而不是上下文菜单本身在上下文菜单上。

这是一个简单的修补程序，但是，因为每个菜单项暴露了一个GetContextMenu$c$c>方法，将告诉你哪些文本菜单包含菜单项。

更改code以下内容：

 私人无效MenuViewDetails_Click（对象发件人，EventArgs的）
{
    //尝试转换发送到一个菜单项
    菜单项菜单项=发件人的菜单项;
    如果（菜单项！= NULL）
    {
        //检索包含该菜单项的文本菜单
        文本菜单菜单= menuItem.GetContextMenu（）;

        //获取，其中显示该上下文菜单控制
        控制sourceControl = menu.SourceControl;
    }
}
 

有关的ContextMenuStrip ：

如果你使用它改变的事情稍微的ContextMenuStrip ，而不是文本菜单。这两个控制是不相关的彼此，和一个的实例不能铸造的其他的实例

与以前一样，项目的被点击了发件人参数仍然是返回，所以你必须确定的ContextMenuStrip 拥有这个人的菜单项。你这样做，与Owner$c$c>物业。最后，您将使用SourceControl$c$c>物业，以确定哪些控制被显示的上下文菜单。

修改您的code像这样：

 私人无效MenuViewDetails_Click（对象发件人，EventArgs的）
{
     //尝试投发件人在ToolStripItem
     ToolStripItem的菜单项=发件人为ToolStripItem的;
     如果（菜单项！= NULL）
     {
        //获取拥有此ToolStripItem的的的ContextMenuStrip
        老板的ContextMenuStrip = menuItem.Owner为的Con​​textMenuStrip;
        如果（老板！= NULL）
        {
           //获取，其中显示该上下文菜单控制
           控制sourceControl = owner.SourceControl;
        }
     }
 }
 

I have a ContextMenuStrip that is assigned to several different listboxes. I am trying to figure out when the ContextMenuStrip is clicked what ListBox it was used on. I tried the code below as a start but it is not working. The sender has the correct value, but when I try to assign it to the menuSubmitted it is null.

private void MenuViewDetails_Click(object sender, EventArgs e)
{
    ContextMenu menuSubmitted = sender as ContextMenu;
    if (menuSubmitted != null)
    {
        Control sourceControl = menuSubmitted.SourceControl;
    }
}

Any help would be great. Thanks.

Using the assistance below, I figured it out:

private void MenuViewDetails_Click(object sender, EventArgs e)
        {
            ToolStripMenuItem menuItem = sender as ToolStripMenuItem;
            if (menuItem != null)
            {
                ContextMenuStrip calendarMenu = menuItem.Owner as ContextMenuStrip;

                if (calendarMenu != null)
                {
                    Control controlSelected = calendarMenu.SourceControl;
                }
            }
        }

For a ContextMenu:

The problem is that the sender parameter points to the item on the context menu that was clicked, not the context menu itself.

It's a simple fix, though, because each MenuItem exposes a GetContextMenu method that will tell you which ContextMenu contains that menu item.

Change your code to the following:

private void MenuViewDetails_Click(object sender, EventArgs e)
{
    // Try to cast the sender to a MenuItem
    MenuItem menuItem = sender as MenuItem;
    if (menuItem != null)
    {
        // Retrieve the ContextMenu that contains this MenuItem
        ContextMenu menu = menuItem.GetContextMenu();

        // Get the control that is displaying this context menu
        Control sourceControl = menu.SourceControl;
    }
}

For a ContextMenuStrip:

It does change things slightly if you use a ContextMenuStrip instead of a ContextMenu. The two controls are not related to one another, and an instance of one cannot be casted to an instance of the other.

As before, the item that was clicked is still returned in the sender parameter, so you will have to determine the ContextMenuStrip that owns this individual menu item. You do that with the Owner property. Finally, you'll use the SourceControl property to determine which control is displaying the context menu.

Modify your code like so:

private void MenuViewDetails_Click(object sender, EventArgs e)
{
     // Try to cast the sender to a ToolStripItem
     ToolStripItem menuItem = sender as ToolStripItem;
     if (menuItem != null)
     {
        // Retrieve the ContextMenuStrip that owns this ToolStripItem
        ContextMenuStrip owner = menuItem.Owner as ContextMenuStrip;
        if (owner != null)
        {
           // Get the control that is displaying this context menu
           Control sourceControl = owner.SourceControl;
        }
     }
 }