谢谢 Thomas，您的解释很有帮助，但您实施的解决方案太慢了.我修改了它以充分利用 Array.Copy.

Thank you Thomas, your explanation was very helpful but your implemented solution is too slow. I modified it to put Array.Copy to good use.

    void ResizeArray<T>(ref T[,] original, int newCoNum, int newRoNum)
    {
        var newArray = new T[newCoNum,newRoNum];
        int columnCount = original.GetLength(1);
        int columnCount2 = newRoNum;
        int columns = original.GetUpperBound(0);
        for (int co = 0; co <= columns; co++)
            Array.Copy(original, co * columnCount, newArray, co * columnCount2, columnCount);
        original = newArray;
    }

这里我假设行数多于列数，因此我将数组构造为 [columns, rows].这样我就可以一次在整个列上使用 Array.Copy(一次比一个单元格快得多).

Here I'm assuming that there are more rows than columns so I structured the array as [columns, rows]. That way I use Array.Copy on an entire column in one shot (much faster than one cell a time).

它只能增加数组的大小，但也可以调整以减小大小.

It only works to increment the size of the array but it can probably be tweaked to reduce the size too.