更新时间:2023-10-24 08:46:46
您在返回与2个属性JSON,成功
和消息
(你不需要 parseJSON
)。要访问它们。
You returning json with 2 properties, Success
and Message
(you do not need parseJSON
). To access them
success: function (result) {
var success = result.Success;
var message = result.Message;
....