更新时间:2023-10-25 15:20:58
$("#list").live('hover', function() {
$("#list").sortable({
update : function () {
var neworder = new Array();
$('#list li').each(function() {
//get the id
var id = $(this).attr("id");
//create an object
var obj = {};
//insert the id into the object
obj[] = id;
//push the object into the array
neworder.push(obj);
});
$.post("pagewhereyouuselist.php",{'neworder': neworder},function(data){});
}
});
});
然后在您的PHP文件中,或在本示例中为"pagewhereyouuselist.php"
Then in your PHP file, or in this example "pagewhereyouuselist.php"
$neworderarray = $_POST['neworder'];
//loop through the list of ids and update your db
foreach($neworderarray as $order=>$id){
//you prob jave a connection already i just added this as an example
$con = mysql_connect("host","username","password");
if (!$con){
die('Could not connect: ' . mysql_error());
}
mysql_select_db("my_db", $con);
mysql_query("UPDATE table SET order = {$order} WHERE id = {$id}");
mysql_close($con);
}
应该这样做 我没有测试它,因为它是一个示例连接.我实际使用的实际脚本更特定于我的程序,这是显示概念的简化版本
that should do it i didn't test it as it is an example connection. the actual script I am actually using is more specific to my program this is a simplified version to show the concept