$发现= FALSE;
的foreach（$值$关键=＆GT; $值）{
    如果（$值 - ＆GT; ID == 4）{
        $找到= TRUE;
        打破;
    }
}如果（$找到）未设置（$值[$关键]）;
 

这被认为是快于任何其他的解决方案，因为我们只遍历阵列来，直到我们找到了对象，我们要删除。

注意：，而迭代，所以我们做的事后这里，您不应该删除数组的元素。

Here is print_r output of my array:

Array
(
[0] => stdClass Object
    (
        [itemId] => 560639000019
        [name] => Item no1
        [code] => 00001
        [qty] => 5
        [id] => 2
    )

[1] => stdClass Object
    (
        [itemId] => 470639763471
        [name] => Second item
        [code] => 76347
        [qty] => 9
        [id] => 4
    )

[2] => stdClass Object
    (
        [itemId] => 56939399632
        [name] => Item no 3
        [code] => 39963
        [qty] => 6
        [id] => 7
    )

)

How can I find index of object with [id] => 4 in order to remove it from array?

$found = false;  
foreach($values as $key => $value) {
    if ($value->id == 4) {
        $found = true;
        break;
    }
}

if ($found) unset($values[$key]);

This is considered to be faster then any other solution since we only iterate the array to until we find the object we want to remove.

Note: You should not remove an element of an array while iterating so we do it afterwards here.