更新时间:2022-05-04 10:03:22
当然有可能.这是一种方法.
It's certainly possible. Here is one way.
d = {'keywords': ['cheap shoes', 'luxury shoes', 'cheap hiking shoes', 'nothing']}
keywords = pd.DataFrame(d,columns=['keywords'])
labels = {'cheap': 'budget', 'luxury': 'expensive', 'hiking': 'sport'}
df = pd.DataFrame(d)
def matcher(k):
x = (i for i in labels if i in k)
return ' | '.join(map(labels.get, x))
df['values'] = df['keywords'].map(matcher)
# keywords values
# 0 cheap shoes budget
# 1 luxury shoes expensive
# 2 cheap hiking shoes budget | sport
# 3 nothing