您使用 for-each-group 但将问题标记为 xslt-1.0，这不有道理.

You use for-each-group but tag the question as xslt-1.0, that does not make sense.

假设使用 XSLT 2.0 处理器，我认为您只是想要

Assuming an XSLT 2.0 processor I think you simply want

<xsl:for-each-group select="$depositAccount/EligibleDepAccount[status = 'Y']" group-by="number"> 
  <xsl:copy-of select="."/>
</xsl:for-each-group>