哦，这是痛。大多数数据库不支持产品聚合功能。您可以使用日志和功能来模拟它。因此，这样的操作可能会起作用：

Oh, this is a pain. Most databases do not support a product aggregation function. You can emulate it with logs and powers. So, something like this might work:

select t.*,
       (select exp(sum(log(serial)))
        from table t2
        where t2.no <= t.no
       ) as cumeProduct
from table t;

请注意，可能会调用 log（）在某些数据库中 ln（）。同样，这适用于正数字。有多种处理负数和零的方法，但这会使答案复杂化（示例数据都是正数）。

Note that log() might be called ln() in some databases. Also, this works for positive numbers. There are variations to handle negative numbers and zeroes, but this complicates the answer (and the sample data is all positive).