是的，还有更好的方法。你真的想看一下原始数据流的章节：

Yes, there is a better way. You really want to look into the chapter of raw-data streaming:

如果您在stream对象中保存原始数据，则可以以任何您喜欢的形式进行读取和写入。所以你的问题的解决方案是

If you hold raw data in a "stream" object, you can read and write it in any form you like. So the solution to your problem is to

• 创建一个流


• 添加图像到流（写入二进制数据）


• 将蒸汽位置重置为开始


• 读取二进制数据字符串

• Create a stream
• Add the "image" to the stream (writing binary data)
• Reset the steam position to the start
• Read out the binary data a string

这是代码：

{
    number sx = 10
    number sy = 10
    image textImg := IntegerImage( "Text", 1, 0 , sx, sy )
    textImg = 97 + random()*26 
    textImg.showimage()

    object stream = NewStreamFromBuffer( 0 )
    ImageWriteImageDataToStream( textImg, stream, 0 )
    stream.StreamSetPos(0,0)
    string asString = StreamReadAsText( stream, 0, sx*sy )
    Result("\n as string:\n\t"+asString)
}

请注意，您可以创建链接到光盘上文件的流，如果您知道起始位置（以字节为单位），也可以直接从文件中读取。

Note that you could create a stream linked to file on disc and, provided you know the starting position in bytes, read from the file directly as well.