Integer.parseInt 无法完成工作，除非您很乐意丢失数据.在这里考虑您的要求.

Integer.parseInt couldn't do the job, unless you were happy to lose data. Think about what you're asking for here.

尝试 Long.parseLong(String) 或 new BigInteger(String) 表示真正的大整数.

Try Long.parseLong(String) or new BigInteger(String) for really big integers.