用户伊朗的权利.无论如何，您的程序有点不干净.我建议您摆脱注释，并使用变量名告诉读者它们应该包含的内容.您想要的可能是这样:

User Eran ist right. Your program is a bit unclean anyway. I suggest you get rid of the comments and use variable names which tell the reader what they are supposed to contain. What you want is probably this:

import java.util.Scanner;

public class Pr8 {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.print("How many numbers do you wish to enter?  ");
        while (!scanner.hasNextInt()) {
            System.err.print("Again, how many numbers?  ");
            scanner.next();
        }
        int numberCount = scanner.nextInt();
        int[] numbers = new int[numberCount];
        for (int i = 0; i < numberCount; i++) {
            String numberString;
            System.out.print("Please enter string #" + (i + 1) + " containing a number:  ");
            scanner.nextLine();
            while ((numberString = scanner.findInLine("[+-]?[0-9]+")) == null) {
                System.err.print("Again, string #" + (i + 1) + " should contain a number:  ");
                scanner.nextLine();
            }
            numbers[i] = Integer.parseInt(numberString);
            System.out.println("Number #" + (i + 1) + " found = " + numbers[i]);
        }
    }
}

示例控制台日志:

How many numbers do you wish to enter?  weewdfsa
Again, how many numbers?  324klj
Again, how many numbers?  5
Please enter string #1 containing a number:  23
Number #1 found = 23
Please enter string #2 containing a number:  sdfsdf
Again, string #2 should contain a number:  werq
Again, string #2 should contain a number:  sdf345df
Number #2 found = 345
Please enter string #3 containing a number:  -34ewr
Number #3 found = -34
Please enter string #4 containing a number:  wqweq+555
Number #4 found = 555
Please enter string #5 containing a number:  xxx-11yyy
Number #5 found = -11