也许您可以尝试：

w <- structure(list(subject = c(1L, 2L, 6L, 7L, 8L, 9L, 16L), sex = structure(c(2L, 
2L, 2L, 2L, 1L, 1L, 1L), .Label = c("F", "M"), class = "factor"), 
response = c(19.08, 16.46, 23.6, 23.96, 22.48, 25.79, 26.66
)), .Names = c("subject", "sex", "response"), class = "data.frame", row.names = c("1", 
"2", "6", "7", "8", "9", "16"))

基于@hadley的评论

Based on @hadley's comments

 eval(substitute(w%>% filter(y=="M"), list(y=as.name(names(w)[2]))))