使用 distinct扩展功能:

Use the distinct extension function:

val a = arrayOf("a", "a", "b", "c", "c")
val b = a.distinct() // ["a", "b", "c"]

还有 distinctBy函数允许您指定如何区分项目:

There's also distinctBy function that allows one to specify how to distinguish the items:

val a = listOf("a", "b", "ab", "ba", "abc")
val b = a.distinctBy { it.length } // ["a", "ab", "abc"]

按照 @ mfulton26 的建议，您也可以使用 toMutableSet ，如果您不需要保留原始顺序，请

As @mfulton26 suggested, you can also use toSet, toMutableSet and, if you don't need the original ordering to be preserved, toHashSet. These functions produce a Set instead of a List and should be a little bit more efficient than distinct.

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