您的接口需要 char * 是C字符串。等效的 ctypes 类型为 c_char_p 。使用：

Your interface takes char* which are C strings. The equivalent ctypes type is c_char_p. Use:

import ctypes
lib = ctypes.WinDLL('example.dll')
VCS_OpenDevice = lib.VCS_OpenDevice
VCS_OpenDevice.argtypes = [ctypes.c_char_p,ctypes.c_char_p,ctypes.c_char_p,ctypes.c_char_p]

DeviceName ='EPOS2'
ProtocolStackName = 'MAXON SERIAL V2'
InterfaceName = 'USB'
PortName = 'USB0'

print VCS_OpenDevice(DeviceName,ProtocolStackName,InterfaceName,PortName)

此外， WinDLL 通常仅Windows系统DLL才需要。如果在C头文件中将接口声明为 __ stdcall ，则 WinDLL 是正确的；否则，请使用 CDLL 。

Also, WinDLL is normally only needed for Windows system DLLs. If your interfaces are declared __stdcall in the C header file, WinDLL is correct; otherwise, use CDLL.

此外，您的返回码记录为 DWORD ** ，这有点奇怪。为什么不使用 DWORD ？如果 DWORD * 是正确的，要访问返回值所指向的DWORD的值，可以使用：

Additionally, your return code is documented as a DWORD*, which is a bit strange. Why not DWORD? If DWORD* is correct, to access the value of the DWORD pointed to by the return value, you can use:

VCS_OpenDevice.restype = POINTER(c_uint32)
retval = VCS_OpenDevice(DeviceName,ProtocolStackName,InterfaceName,PortName)
print retval.contents.value