更新时间:2023-11-09 23:26:16
查看应用程序工厂 ,这应该做你想要的。您将创建一个返回您的Flask应用程序的工厂,您将发送记录器 - 如下所示:
def create_app (logger_instance):
app = Flask(__ name__)
app.config ['LOGGER'] = logger_instance
return app
然后在你的runserver.py中创建并传入记录器:
from yourapp import create_app $ b $ if if __name__ =='__main__':
logger = MyProcess()
app = create_app(logger)
app.run()
完成后,您的应用程序可以引用 app.config中的记录器[ 'LOGGER']
。
I got a doubt about how to pass an object to a flask app in the correct way.
The idea is simple.
I wan to create an api for my application, which means that http requests processed by my flask application will trigger meothds in my main application.
For that, I need flask to be aware of my other process, one way or another.
Currently, I have something like :
if __name__ == '__main__':
Logger = MyProcess()
app.run()
I need to be able to do something like that :
@app.route('/nb_trendy')
def nb_trendy():
res = Logger.get_trendy()
return jsonify(res)
which means that I either need to either give a handle on Logger to app, or directly define Logger inside app.
But in each of the solutions I can find, I need to create a that inherits app, to either override __init__()
and takes objects as parameters, or modify the run()
method.
the current way I would do it is though :
class MyFlask(Flask):
def __init__():
Flask.__init__()
Logger = MyProcess()
Is this also the way you would do it, or is there a better way to do this?
Thanks!
Here is a more general version of this question: Web API in Flask
Take a look at application factories, which should do what you're looking for. You'd create a factory that returned your Flask app that you'd send the logger to - something like this:
def create_app(logger_instance):
app = Flask(__name__)
app.config['LOGGER'] = logger_instance
return app
And then in your runserver.py, you'd create and pass in the logger:
from yourapp import create_app
if __name__ == '__main__':
logger = MyProcess()
app = create_app(logger)
app.run()
Once that's done, your app can refer to the logger inside app.config['LOGGER']
.