您不能从异步调用中返回View. Ajax请求的目的是避免执行整个页面周期.

You can not return a View from an asynchronous call. An ajax request is meant to avoid doing an entire page cycle.

如果您要返回新的View，则只需返回POST.

You should just do a POST back if you want a new View to be returned.

另一个选择是在ajax调用成功后进行回调，并将window.location设置为新的View，以便页面将GET设置为新的View.

The other option would to be have a callback upon success of the ajax call and set the window.location to the new View so the page does a GET to the new View.