更新时间:2023-11-12 11:52:34
根据 https://stripe.com/docs/api?lang=python#errors 你没有处理条带库提供的所有可能的错误/异常.处理财务数据理应更加谨慎,因此您确实至少需要执行以下操作:
According to https://stripe.com/docs/api?lang=python#errors you're not handling all the possible errors/exceptions that the stripe library supplies. And dealing with financial data rightfully deserves even more caution so you really need to do at least something like:
class ChargeCustomerCard(webapp2.RequestHandler):
def post(self):
stripe.api_key = stripeApiKey
customerID = self.request.get("cust")
amount = self.request.get("amt")
try:
charge = stripe.Charge.create(amount=int(amount),currency="usd",customer=customerID,description=customerID)
except stripe.error.CardError, e:
output = {"result":e}
except Exception as e:
# handle this e, which could be stripe related, or more generic
pass
else:
output = {"result":"1"}
self.response.out.write(json.dumps(output))
或者甚至基于官方文档,一个更全面的像:
Or even based on the official documentation, a more comprehensive one like:
try:
# Use Stripe's library to make requests...
pass
except stripe.error.CardError, e:
# Since it's a decline, stripe.error.CardError will be caught
body = e.json_body
err = body['error']
print "Status is: %s" % e.http_status
print "Type is: %s" % err['type']
print "Code is: %s" % err['code']
# param is '' in this case
print "Param is: %s" % err['param']
print "Message is: %s" % err['message']
except stripe.error.RateLimitError, e:
# Too many requests made to the API too quickly
pass
except stripe.error.InvalidRequestError, e:
# Invalid parameters were supplied to Stripe's API
pass
except stripe.error.AuthenticationError, e:
# Authentication with Stripe's API failed
# (maybe you changed API keys recently)
pass
except stripe.error.APIConnectionError, e:
# Network communication with Stripe failed
pass
except stripe.error.StripeError, e:
# Display a very generic error to the user, and maybe send
# yourself an email
pass
except Exception, e:
# Something else happened, completely unrelated to Stripe
pass