尝试此测试:

any(substring in string for substring in substring_list)

如果string中包含任何substring_list中的子字符串，它将返回True.

It will return True if any of the substrings in substring_list is contained in string.

请注意，有一个

Note that there is a Python analogue of Marc Gravell's answer in the linked question:

from itertools import imap
any(imap(s.__contains__, substring_list))

使用生成器表达式的上述版本可能更清晰.

Probably the above version using a generator expression is clearer though.