不要那样做 - 将响应视为字符串，并尝试通过字符串替换来获取数据.

Do not do that - treat the response as a string, and try to get you data out through string replace.

响应是一个对象 - 一个元组列表，它实际上是这样的:

The response is an object - a list of tuples, it actually looks like this:

[('ABC',),]

列表中的每个元组都是一个响应行；元组的每个成员都是该行中的一列.

Every tuple in the list is a response row; every member of the tuple is a column in that row.

要获得第一行的第一列，您只需寻址它们(它们的索引从 0 开始):

To get the first column of the first row, you just address them (their indices start from 0):

${value}=    Set Variable    ${the response object}[0][0]

例如，如果查询返回 3 行，每行 2 列:

If for example the query returnes 3 rows, each with 2 columns:

[('ABC', 'DEF'), ('GHI', 'JKL'), ('MNO', 'PQR')]

，你会得到第三行(索引:2)第二列(索引:1) - 字符串'PQR' - 用这个:

, you'd get the 3rd row's (index: 2) 2nd column (index: 1) - the string 'PQR' - with this:

${value}=    Set Variable    ${the response object}[2][1]

现在我希望你明白为什么使用字符串替换(在二维列表的字符串表示上)不是一个好主意.

Now I hope you understand why using string replace (over the string representation of a two-dimensional list) is not a good idea.