Lists.transform()确实像您怀疑的那样执行缓慢.您可以做以下其中一项

Lists.transform() does perform lazily as you suspected. You could do one of

Lists.newArrayList(Lists.transform(...))

或者，如果您想要一个不变的版本，

or, if you want an immutable version,

ImmutableList.copyOf(Lists.transform(...))

，然后序列化结果列表.

and then serialize the resulting list.