您未指定要如何组合提供的值.

You didn’t specify how you want to combine the supplied values.

如果您想让值交替出现，则解决方案是:

If you want to have the values alternating, a solution would be:

Stream.generate(supplier1).flatMap(x->Stream.of(x, supplier2.get()))

如果您想要配对，可以使用

If you want to have some kind of pair, you can use

Stream.generate(()->new Pair<>(supplier1.get(), supplier2.get()))

尽管您可以编写 Pair 类，因为jdk不提供此类.(您可能会滥用 AbstractMap.SimpleEntry ，但这很讨厌).

though it is up to you to write the Pair class as the jdk does not offer such a class. (You could abuse AbstractMap.SimpleEntry but that’s rather nasty).

如果您有一个有限的 Stream ，则可以使用 limit 另一个流，所以这不是一个通用的解决方案.

If you have a finite Stream you can use Stream.concat to create a stream which will process all items of the first stream before the items of the second, however, streams created using a Supplier are infinite by default so you have to use limit on the first stream before you can concat it to another stream, so it’s not a general solution.

如果您要查询每个供应商一次，则可以使用

If you want to query each Supplier exactly once, you can use

Stream.of(supplier1, supplier2).map(Supplier::get)

当然，如果您不需要对 Supplier s进行懒惰的评估，则可以

though, of course, if you don’t need lazy evaluation of the Suppliers, a

Stream.of(supplier1.get(), supplier2.get())

也会这样做.