更新时间:2023-11-17 19:52:58
In the following it is shown how to implement a QStackedWidget
with 2 buttons, the basic idea is to layout the design, for this we analyze that a QVBoxLayout
must be placed to place the QStackedWidget
and another layout, this second layout will be a QHBoxLayout
to have the buttons. Then we connect the signals that handle the transition between pages. Also in this example I have created 3 types of widgets that will be placed on each page.
from PyQt5.QtWidgets import *
class Widget1(QWidget):
def __init__(self, parent=None):
QWidget.__init__(self, parent=parent)
lay = QVBoxLayout(self)
for i in range(4):
lay.addWidget(QPushButton("{}".format(i)))
class Widget2(QWidget):
def __init__(self, parent=None):
QWidget.__init__(self, parent=parent)
lay = QVBoxLayout(self)
for i in range(4):
lay.addWidget(QLineEdit("{}".format(i)))
class Widget3(QWidget):
def __init__(self, parent=None):
QWidget.__init__(self, parent=parent)
lay = QVBoxLayout(self)
for i in range(4):
lay.addWidget(QRadioButton("{}".format(i)))
class stackedExample(QWidget):
def __init__(self, parent=None):
QWidget.__init__(self, parent=parent)
lay = QVBoxLayout(self)
self.Stack = QStackedWidget()
self.Stack.addWidget(Widget1())
self.Stack.addWidget(Widget2())
self.Stack.addWidget(Widget3())
btnNext = QPushButton("Next")
btnNext.clicked.connect(self.onNext)
btnPrevious = QPushButton("Previous")
btnPrevious.clicked.connect(self.onPrevious)
btnLayout = QHBoxLayout()
btnLayout.addWidget(btnPrevious)
btnLayout.addWidget(btnNext)
lay.addWidget(self.Stack)
lay.addLayout(btnLayout)
def onNext(self):
self.Stack.setCurrentIndex((self.Stack.currentIndex()+1) % 3)
def onPrevious(self):
self.Stack.setCurrentIndex((self.Stack.currentIndex()-1) % 3)
if __name__ == '__main__':
import sys
app = QApplication(sys.argv)
w = stackedExample()
w.show()
sys.exit(app.exec_())