如果冲洗STD不工作，然后尝试读取多余的字符和丢弃，所建议的这里。

这将工作：

 的#include＆LT;＆string.h中GT;
＃包括LT＆;＆stdio.h中GT;诠释主（）{
    焦农布雷[10];
    烧焦mensaje [80];
    焦炭℃;    的printf（键入您的姓名：\\ n）;
    scanf函数（％S，农布雷）;    而（（C =的getchar（））='\\ n'和;！＆安培;！C = EOF）
            / * *丢弃/;    的printf（现在，键入一条消息：\\ n）;
    得到（mensaje）;    的printf（％S：％S，农布雷，mensaje）;
    返回0;
}
 

After wasting too much time searching why my program doesn't execute gets() after using scanf(), I found a solution which is to use fflush(stdin) after scanf() to enable gets() to get a string.

The problem is that fflush(stdin) doesn't do what is expected from it: The program continues skipping gets() and I can't write any phrase in the console to be read.

My code is the next one:

#include <string.h>
#include <stdio.h>

int main(){
    char nombre[10];
    char mensaje[80];

    printf("Type your name:\n");
    scanf("%s", nombre);

    fflush(stdin);

    printf("Now, type a message:\n");
    gets(mensaje);

    printf("3/%s:%s",nombre,mensaje);
    return 0;
}

If flushing std doesn't work, then try reading in the extra characters and discarding, as suggested here.

This will work:

#include <string.h>
#include <stdio.h>

int main(){
    char nombre[10];
    char mensaje[80];
    char c;

    printf("Type your name:\n");
    scanf("%s", nombre);

    while((c= getchar()) != '\n' && c != EOF)
            /* discard */ ;

    printf("Now, type a message:\n");
    gets(mensaje);

    printf("%s:%s",nombre,mensaje);
    return 0;
}